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4..Mr.chan poured 1 kg of water at100℃into 1kg of liquid nitrogen at -195℃Given that:Specific heat capacity of water = 4200Jkg-1℃-1Specific latent heat of fusion of ice = 336000Jkg-1Specific heat capacity of nitrogen gas = 1040Jkg-1℃-1Specific latent heat of vaporization of nitrogen =... 顯示更多 4..Mr.chan poured 1 kg of water at100℃into 1kg of liquid nitrogen at -195℃ Given that: Specific heat capacity of water = 4200Jkg-1℃-1 Specific latent heat of fusion of ice = 336000Jkg-1 Specific heat capacity of nitrogen gas = 1040Jkg-1℃-1 Specific latent heat of vaporization of nitrogen = 200000Jkg-1 4a...Calculate the energy required to change 1 kg liquid nitrogen at -195℃ to 0℃ nitrogen gas 4b..Calculate the energy lost by the 1 kg water at 100℃changed to 0℃..By using(a)(b),whet will be the final state of the mixture? 4c....Find the final temperature of the mixture

最佳解答:

(a) Energy required = (1 x 200000 + 1 x 1040 x 195) J = 402 800 J (b) Energy lost by water = 1 x 4200 x 100 J = 420 000 J The final state of the mixture is nitorgen gas and liquid water (c) Let T be the final temperature, hence 1 x 200000 + 1040 x (T+195) = 1 x 4200 x (100-T) solve for T gives T = 3.1'C

其他解答:0D7DAC4E6DF60DFA

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